| ⇦ | 
| ⇨ |
The rate constant of the reaction A → B is 0.6 ˣ 10⁻³ mol per second. If the concentration of A is 5 M, then concentration of B after 20 minutes is
Options
(a) 3.60 M
(b) 0.36 M
(c) 0.72 M
(d) 1.08 M
Correct Answer:
0.72 M
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - C₆H₆ consists of one ring,while naphthalene consists of two rings. Both
- Diamond is used I glass cutting due to its
- Which one of the following is the heaviest
- The reagent commonly used to determine hardness of water titrimetrically is
- Which responds to +ve iodoform test
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- C₆H₆ consists of one ring,while naphthalene consists of two rings. Both
- Diamond is used I glass cutting due to its
- Which one of the following is the heaviest
- The reagent commonly used to determine hardness of water titrimetrically is
- Which responds to +ve iodoform test
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Reaction is of zero order as the unit of rate constant is mol L⁻¹ S⁻¹
.·. Concentration of B =k × t =0.6×10⁻³ × 20 × 60 = 0.72 M
Let at time t=0 (A)= a and (B)=0
At time t=(20*60)sec (A)= (a-x) and (B)=x then
For 1st order reaction
(A’) =(A) – kt
: a-x = a – 0.6*10-3*20*60
Solving it will give
X= 0.72 M