| ⇦ |
| ⇨ |
The pressure and temperature of 4 dm³ of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be
Options
(a) 2 dm³
(b) 3 dm³
(c) 4 dm³
(d) 8 dm³
Correct Answer:
4 dm³
Explanation:
P₁ = P , V₁ = 4 dm³, T₁ = T. P₂ = 2P, V₂ = ?, T₂ = 2T. From gas equation, P₁V₁ / T₁ = P₂V₂ / T₂ ⇒ P * 4 / T = 2P * V / 2T. ⇒ V = 4dm³.
Related Questions: - Standard electrode potential for Sn⁴⁺/Sn²⁺ couple is +0.15 V and that for the
- Set of isoelectronic species is
- If 1 litre of N₂ is mixed with 2 litre of O₂, quantity explaining it is
- Main constituents of LPG is
- When a neutral atom is converted into a cation, there is
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Standard electrode potential for Sn⁴⁺/Sn²⁺ couple is +0.15 V and that for the
- Set of isoelectronic species is
- If 1 litre of N₂ is mixed with 2 litre of O₂, quantity explaining it is
- Main constituents of LPG is
- When a neutral atom is converted into a cation, there is
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply