| ⇦ | 
| ⇨ |
The pressure and temperature of 4 dm³ of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be
Options
(a) 2 dm³
(b) 3 dm³
(c) 4 dm³
(d) 8 dm³
Correct Answer:
4 dm³
Explanation:
P₁ = P , V₁ = 4 dm³, T₁ = T. P₂ = 2P, V₂ = ?, T₂ = 2T. From gas equation, P₁V₁ / T₁ = P₂V₂ / T₂ ⇒ P * 4 / T = 2P * V / 2T. ⇒ V = 4dm³.
Related Questions: - Which of the following is most volatile
- Reaction of diborane with ammonia gives initially
- For the reaction R → P a graph of [R] against time is found to be a straight
- The normality of solution containing 31.5g of hydrated oxalic acid (H₂C₂O₄.2H₂O)
- A drug which is sturcturally related to adrenaline is
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is most volatile
- Reaction of diborane with ammonia gives initially
- For the reaction R → P a graph of [R] against time is found to be a straight
- The normality of solution containing 31.5g of hydrated oxalic acid (H₂C₂O₄.2H₂O)
- A drug which is sturcturally related to adrenaline is
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply