| ⇦ | 
| ⇨ |
The pressure and temperature of 4 dm³ of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be
Options
(a) 2 dm³
(b) 3 dm³
(c) 4 dm³
(d) 8 dm³
Correct Answer:
4 dm³
Explanation:
P₁ = P , V₁ = 4 dm³, T₁ = T. P₂ = 2P, V₂ = ?, T₂ = 2T. From gas equation, P₁V₁ / T₁ = P₂V₂ / T₂ ⇒ P * 4 / T = 2P * V / 2T. ⇒ V = 4dm³.
Related Questions: - The chemical substance used for the treatments of
- Nitrobenzene, on nitration,produces
- Nitrobenzene combines with hydrogen in the presence of platinum to yield
- Which of the following hormones is produced under the conditions of stress
- when a manganous salt is fused with a mixture of KNO₃ and solid NaOH
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The chemical substance used for the treatments of
- Nitrobenzene, on nitration,produces
- Nitrobenzene combines with hydrogen in the presence of platinum to yield
- Which of the following hormones is produced under the conditions of stress
- when a manganous salt is fused with a mixture of KNO₃ and solid NaOH
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply