| ⇦ | 
| ⇨ |
The potential energy of particle in a force field is U = A/r² – b/r, where A and B are positive constants and r is the distance of particle from the centre of the field. For stable equilibrium, the distance of the particle is:
Options
(a) B / 2A
(b) 2A / B
(c) A / B
(d) B / A
Correct Answer:
2A / B
Explanation:
for equilibrium dU/ dr = 0
-2A/r³ + B/r² = 0 r = 2A / B
for stable equilibrium d²U /dr² should be positive for the value of r.
here d²U / dr² = 6A/r⁴ – 2B/r³ is +ve value for r = 2A / B So.
Related Questions: - The period of a simple pendulum inside a stationary lift is T. The lift accelerates
- Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
- A concave mirror of focal length f₁ is placed at a distance d from a convex lens
- Which of the following figures represent the variation of particle momentum
- A jar is filled with two non-mixing liquids 1 and 2 having densities
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The period of a simple pendulum inside a stationary lift is T. The lift accelerates
- Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
- A concave mirror of focal length f₁ is placed at a distance d from a convex lens
- Which of the following figures represent the variation of particle momentum
- A jar is filled with two non-mixing liquids 1 and 2 having densities
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply