| ⇦ |
| ⇨ |
The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. The number of electrons striking the target per second is
Options
(a) 5 x 10¹⁶
(b) 1 x 10¹⁷
(c) 4 x 10¹⁵
(d) 2 x 10¹⁶
Correct Answer:
2 x 10¹⁶
Explanation:
Let n = number of electrons striking per sec.
e = 1.6 × 10⁻¹⁹ = charge on each electron
Charge per second = n × 1.6 × 10⁻¹⁹
Current = n × 1.6 × 10⁻¹⁹
3.2 × 10⁻³ = n × 1.6 × 10⁻¹⁹
n = 3.2 × 10⁻³ / 1.6 × 10⁻¹⁹ = 2 × 10¹⁶
Related Questions: - A capacitor of 2.5 μF is charged through a resistor of 4 MΩ. In how much time
- The time period of bar magnet is doubled when magnetic field is reduced
- After 300 days, the activity of a radioactive sample is 5000 dps
- The speed of electromagnetic waves in vaccum is equal to
- What should be the velocity(v) of a sound source moving towards a stationary observer
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A capacitor of 2.5 μF is charged through a resistor of 4 MΩ. In how much time
- The time period of bar magnet is doubled when magnetic field is reduced
- After 300 days, the activity of a radioactive sample is 5000 dps
- The speed of electromagnetic waves in vaccum is equal to
- What should be the velocity(v) of a sound source moving towards a stationary observer
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply