⇦ | ![]() | ⇨ |
The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. The number of electrons striking the target per second is
Options
(a) 5 x 10¹⁶
(b) 1 x 10¹⁷
(c) 4 x 10¹⁵
(d) 2 x 10¹⁶
Correct Answer:
2 x 10¹⁶
Explanation:
Let n = number of electrons striking per sec.
e = 1.6 × 10⁻¹⁹ = charge on each electron
Charge per second = n × 1.6 × 10⁻¹⁹
Current = n × 1.6 × 10⁻¹⁹
3.2 × 10⁻³ = n × 1.6 × 10⁻¹⁹
n = 3.2 × 10⁻³ / 1.6 × 10⁻¹⁹ = 2 × 10¹⁶
Related Questions:
- A horizontal straight conductor kept in north-south direction falls under gravity. Then
- A photoelectric surface is illuminated successively by monochromatic light of wavelength
- A ray of light is incident on a transparent glass slab of refractive index 1.62
- The velocity of image when object and mirror both are moving towards each other
- A transformer rated at 10 kW is used to connect a 5 kV transmission line to a 240 V
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply