The phase difference between the flux linked with a coil rotating in a uniform

The phase difference between the flux linked with a coil rotating in a uniform magnetic field and induced emf produced in it is

Options

(a) π/2
(b) π/3
(c) (-π/6)
(d) π

Correct Answer:

π/2

Explanation:

The flux ɸ = B.A = |B| |A| cos θ

Also, induced emf, ε = – (dɸ / dt) = (d |B| |A| cos θ) / dt

= – |B| |A| [d cos θ / dt] = |B| |A| sin θ. ω

ε = BA ω cos [θ – (π / 2)]

admin:

Related Questions

  1. A vertical spring with force constant k is fixed on a table. A ball of mass
  2. If we study the vibration of a pipe open at both ends
  3. A coil of self-inductance L is connected in series with a bulb B and an AC source
  4. If the red light is replaced by blue light illuminating the object in a microscope
  5. If the nucleus ²⁷₁₃Al has nuclear radius of about 3.6 fm