| ⇦ | 
| ⇨ |
The oxidation states of sulphur in the anions : SO₃²⁻,S₂O₄²⁻ and S₂O₆²⁻ follow the order
Options
(a) S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
(b) SO₃²⁻ < S₂O₄²⁻ < S₂O₆²⁻
(c) S₂O₄²⁻ < S₂O₆²⁻ < SO₃²⁻
(d) S₂O₆²⁻ < S₂O₄²⁻ < SO₃²⁻
Correct Answer:
S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Absolute temperature is the temperature at which
- For vaporization of water at 1 atmospheric pressure, the values of ΔH and ΔS
- Aqueous solutions of hydrogen sulphide and sulphur dioxide when mixed together
- What is the maximum number of orbitals that can be identified with the following
- The number of gram molecules of oxygen in 6.02 x 10²⁴ CO molecules is
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Absolute temperature is the temperature at which
- For vaporization of water at 1 atmospheric pressure, the values of ΔH and ΔS
- Aqueous solutions of hydrogen sulphide and sulphur dioxide when mixed together
- What is the maximum number of orbitals that can be identified with the following
- The number of gram molecules of oxygen in 6.02 x 10²⁴ CO molecules is
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply