| ⇦ | 
| ⇨ |
The original temperature of a black body is 727⁰C. The temperature at which this black body must be raised so as to double the total radiant energy is
Options
(a) 971 K
(b) 1190 K
(c) 2001 K
(d) 1458 K
Correct Answer:
1190 K
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A ray enters a glass sphere of refractive index μ=√3 at an angle of incidence of 60⁰
- The excess pressure inside one soap bubble is three times that inside a second soap bubble
- For the normal eye, the cornea of eye provides a converging power of 40D
- Equal currents are passing through two very long and straight parallel wires
- The moment of inertia of a semicircular ring about the centre is
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A ray enters a glass sphere of refractive index μ=√3 at an angle of incidence of 60⁰
- The excess pressure inside one soap bubble is three times that inside a second soap bubble
- For the normal eye, the cornea of eye provides a converging power of 40D
- Equal currents are passing through two very long and straight parallel wires
- The moment of inertia of a semicircular ring about the centre is
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply