| ⇦ |
| ⇨ |
The original temperature of a black body is 727⁰C. The temperature at which this black body must be raised so as to double the total radiant energy is
Options
(a) 971 K
(b) 1190 K
(c) 2001 K
(d) 1458 K
Correct Answer:
1190 K
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A condenser has a capacity 2 μF and is charged to a voltage of 50 V. The energy
- In a n-p-n transistor about 10¹⁰ electrons enter the emitter in 2 μs,
- Two waves of same amplitude superpose. The resultant intensity is I₁
- In gamma ray emission from a nucleus
- A coil of N turns and mean cross-sectional area A is rotating with uniform angular
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A condenser has a capacity 2 μF and is charged to a voltage of 50 V. The energy
- In a n-p-n transistor about 10¹⁰ electrons enter the emitter in 2 μs,
- Two waves of same amplitude superpose. The resultant intensity is I₁
- In gamma ray emission from a nucleus
- A coil of N turns and mean cross-sectional area A is rotating with uniform angular
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply