| ⇦ | 
| ⇨ |
The most stable conformation of n-butane is
Options
(a) gauche
(b) staggered
(c) skew boat
(d) eclipsed
Correct Answer:
staggered
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Of the following, which change will shift the reaction towards the product
- Which of the following technique is most suitable for purification of cyclo
- Decreasing order of stability of O₂ , O₂⁻ , O₂⁺ and O₂²⁻ is
- MnO₄²⁻ (1 mole) in neutral aqueous medium is disproportionated to
- For spontaneous reaction
Topics: Hydrocarbons
(84)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Of the following, which change will shift the reaction towards the product
- Which of the following technique is most suitable for purification of cyclo
- Decreasing order of stability of O₂ , O₂⁻ , O₂⁺ and O₂²⁻ is
- MnO₄²⁻ (1 mole) in neutral aqueous medium is disproportionated to
- For spontaneous reaction
Topics: Hydrocarbons (84)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Because in staggered or anti form two CH3 groups are in opposite direction and there is less torsional strai