The momentum of a particle having a de Broglie wavelength of 10⁻¹⁷metres is

The Momentum Of A Particle Having A De Broglie Wavelength Chemistry Question

The momentum of a particle having a de Broglie wavelength of 10⁻¹⁷metres is (Given h= 6.625 × 10⁻³⁴Js)

Options

(a) 3.3125 x 10⁻⁷kg ms⁻¹
(b) 26.5 x 10⁻⁷kg ms⁻¹
(c) 6.625 x 10⁻¹⁷kg ms⁻¹
(d) 13.25 x 10⁻¹⁷kg ms⁻¹

Correct Answer:

6.625 x 10⁻¹⁷kg ms⁻¹

Explanation:

According to de broglie ‎λ=h/mv ⇒ mv= h/λ = 6.626 x 10⁻³⁴ /10⁻¹⁷ = 6.626 x 10⁻¹⁷ kg m/s.

Related Questions:

  1. The metal having the highest melting point is
  2. If a compound, on analysis was found to contain C=18.5% ,H=1.55%, Cl=55.04%
  3. If Avogadro number NA, is charged from 6.022 ˣ 10²³ mol⁻¹ to 6.022 ˣ 10²⁰ mol⁻¹
  4. On reaction with Mg, very dilute nitric acid produces
  5. Of the following reaction, only one is a redox reaction.Identify this reaction

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*