| ⇦ | 
| ⇨ |
The maximum number of possible interference maxima for slit-seperation equal to twice the wavelength, in young’s double slit experiment is
Options
(a) Infinite
(b) five
(c) three
(d) zero
Correct Answer:
five
Explanation:
For interference maxima, d sin θ = nλ
⇒ 2λ sin θ = nλ ⇒ sin θ = n / 2
sin θ can have values between 0 and ±1.
Hence n can be (-2, -1, 0, +1, +2) or five values.
The possible maxima are five.
Related Questions: - The refractive index of water, glass and diamond are 1.33, 1.50, 2.40 respectively
- The charges Q, +q, and +q are placed at the vartices of an equilateral
- A liquid boils when its vapour pressure equals
- A ball is dropped into a well in which the water level is at a depth h below the top
- The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The refractive index of water, glass and diamond are 1.33, 1.50, 2.40 respectively
- The charges Q, +q, and +q are placed at the vartices of an equilateral
- A liquid boils when its vapour pressure equals
- A ball is dropped into a well in which the water level is at a depth h below the top
- The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply