| ⇦ | 
| ⇨ |
The ionisation energy of an electron in the ground state of helium atom is 24.6 eV. The energy required to remove both the electron is
Options
(a) 51.8 eV
(b) 79 eV
(c) 38.2 eV
(d) 49.2 eV
Correct Answer:
79 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If the momentum of electron is changed by P, then the de-Broglie wavelength
- The radius of the first orbit of the hydrogen atom is a₀. The radius of the second orbit
- The sun light reaches us as white and not as its components because
- Three fourth of the active material decays in a radioactive sample in 3/4 sec
- A coil of resistance 20 ohm and inductance 5H is connected with a 100V battery
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the momentum of electron is changed by P, then the de-Broglie wavelength
- The radius of the first orbit of the hydrogen atom is a₀. The radius of the second orbit
- The sun light reaches us as white and not as its components because
- Three fourth of the active material decays in a radioactive sample in 3/4 sec
- A coil of resistance 20 ohm and inductance 5H is connected with a 100V battery
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply