⇦ | ![]() | ⇨ |
The ionisation energy of an electron in the ground state of helium atom is 24.6 eV. The energy required to remove both the electron is
Options
(a) 51.8 eV
(b) 79 eV
(c) 38.2 eV
(d) 49.2 eV
Correct Answer:
79 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- The de-Broglie wavelength of an electron moving with a velocity 1.5×10⁸ ms⁻¹ is equal
- The pressure at the bottom of a tank containing a liquid does not depend on
- In a circuit, the current lags behind the voltage by a phase difference of π/2.
- A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor.
- A particle has initial velocity (3i + 4j) and acceleration (0.1 i+0.3j). It’s speed after 10s
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply