| ⇦ |
| ⇨ |
The ionisation energy of an electron in the ground state of helium atom is 24.6 eV. The energy required to remove both the electron is
Options
(a) 51.8 eV
(b) 79 eV
(c) 38.2 eV
(d) 49.2 eV
Correct Answer:
79 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A lead bullet of 10 gm travelling at 300 m/s strikes against a block
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
- An oscillator circuit consists of an inductance of 0. mH and a capacitor of 20 μF.
- The speed of light in media M₁ and M₂ are 1.5×10⁸ ms⁻¹ and 2×10⁸ ms⁻¹ respectively.
- The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A lead bullet of 10 gm travelling at 300 m/s strikes against a block
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
- An oscillator circuit consists of an inductance of 0. mH and a capacitor of 20 μF.
- The speed of light in media M₁ and M₂ are 1.5×10⁸ ms⁻¹ and 2×10⁸ ms⁻¹ respectively.
- The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply