| ⇦ | 
| ⇨ |
The intensity at the maximum in a Young’s double slit experiment is I₀. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance, D= 10 d?
Options
(a) I₀/4
(b) 3/4 I₀
(c) I₀/2
(d) I₀
Correct Answer:
I₀/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - When light of wavelength 300 nm falls on a photoelectric emitter,
- Following figures show the arrangement of bar magnets in different configurations
- A boat which has a speed of 5 kmh⁻¹ in still water crosses river of width 1 km long
- The minimum wavelength of X-rays emitted by X-ray tube is 0.4125Å
- The work function of sodium is 2.3 eV. The threshold wavelength of sodium will be
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When light of wavelength 300 nm falls on a photoelectric emitter,
- Following figures show the arrangement of bar magnets in different configurations
- A boat which has a speed of 5 kmh⁻¹ in still water crosses river of width 1 km long
- The minimum wavelength of X-rays emitted by X-ray tube is 0.4125Å
- The work function of sodium is 2.3 eV. The threshold wavelength of sodium will be
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply