⇦ | ⇨ |
The intensity at the maximum in a Young’s double slit experiment is I₀. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance, D= 10 d?
Options
(a) I₀/4
(b) 3/4 I₀
(c) I₀/2
(d) I₀
Correct Answer:
I₀/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Consider a compound slab consisting of two different materials having equal thickness
- α-particles, deuterons and protons of same energy are moving in a perpendicular
- Suppose for some reasons, radius of earth were to shrink by 1% of present value,
- Lumen is the unit of
- When the temperature increases, the viscocity of
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Consider a compound slab consisting of two different materials having equal thickness
- α-particles, deuterons and protons of same energy are moving in a perpendicular
- Suppose for some reasons, radius of earth were to shrink by 1% of present value,
- Lumen is the unit of
- When the temperature increases, the viscocity of
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply