| ⇦ |
| ⇨ |
The intensity at the maximum in a Young’s double slit experiment is I₀. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance, D= 10 d?
Options
(a) I₀/4
(b) 3/4 I₀
(c) I₀/2
(d) I₀
Correct Answer:
I₀/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The angle of a prism is A. One of its refracting surfaces is silvered
- In atom bomb, the reaction which occurs is
- For a satellite escape velocity is 11 kms⁻¹.If the satellite is launched at an angle
- Application of Bernoulli’s theorem can be seen in
- Which of the following is not a transverse wave?
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The angle of a prism is A. One of its refracting surfaces is silvered
- In atom bomb, the reaction which occurs is
- For a satellite escape velocity is 11 kms⁻¹.If the satellite is launched at an angle
- Application of Bernoulli’s theorem can be seen in
- Which of the following is not a transverse wave?
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply