| ⇦ | 
| ⇨ |
The horizontal range and maximum height of a projectile are equal.The angle of projection is
Options
(a) θ=tan⁻¹(1/4)
(b) θ=tan⁻¹(4)
(c) θ=tan⁻¹(2)
(d) θ=45ﾟ
Correct Answer:
θ=tan⁻¹(4)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A luminous object is seperated from a screen by distance d. A convex lens
- A body of mass 10 kg is moving on an inclined plane of inclination 30°with an acceleration
- A uniform force of (3i+j) Nacts on a particle of mass 2 kg.Hence the particle is displaced
- A force F=ai+3j+6k is acting at a point r=2i-6j-12k. The value of α for
- Three objects A,B and C are kept in a straight line on a frictionless horizontal surface
Difficulty Level: Easy
(1008)
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A luminous object is seperated from a screen by distance d. A convex lens
- A body of mass 10 kg is moving on an inclined plane of inclination 30°with an acceleration
- A uniform force of (3i+j) Nacts on a particle of mass 2 kg.Hence the particle is displaced
- A force F=ai+3j+6k is acting at a point r=2i-6j-12k. The value of α for
- Three objects A,B and C are kept in a straight line on a frictionless horizontal surface
Difficulty Level: Easy (1008)
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply