⇦ | ![]() | ⇨ |
The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T and the dip is tan⁻¹ (4/3). A metal rod of length 0.25m is placed in N-S direction and is moved at a constant speed of 10 cms⁻¹ towards the east. The emf induced in the rod will be
Options
(a) 1μV
(b) 5μV
(c) 7μV
(d) 10μV
Correct Answer:
10μV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- The distance of a geo-stationary satellite from the centre of the earth is nearest to
- Given a sample of radium-226 having half-life of 4 days. Find the probability,
- The photoelectric threshold wevelength for potassium (work function being 2 eV) is
- Two parallel long wires carry currents i₁ and i₂ with i₁ > i₂ .
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply