| ⇦ | 
| ⇨ |
The first ionization potentials (eV) of Be and B respectively are
Options
(a) 8.29, 9.32
(b) 9.32, 9.32
(c) 8.29, 8.29
(d) 9.32, 8.29
Correct Answer:
9.32, 8.29
Explanation:
First ionisation potential of Be is greater than boron due to following configuration ₄Be=1s²,2s² ₅B=1s²,2s²2p¹ Order of attraction of electrons towards nucleus 2s>2p, so more amount of energy is required to remove the electron with 2s-orbital in comparison to 2p orbital
Related Questions: - Transition metals show paramagnetism
- Number of moles of MnO₄⁻ required to oxidize one mole of ferrous oxalate
- The C – C bond length in ethane is
- The reaction between an alkyl halide and an alkoxide ion to give an ether is
- Correct order of the stability of group IIA metal carbonates is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Classification of Elements and Periodicity
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Transition metals show paramagnetism
- Number of moles of MnO₄⁻ required to oxidize one mole of ferrous oxalate
- The C – C bond length in ethane is
- The reaction between an alkyl halide and an alkoxide ion to give an ether is
- Correct order of the stability of group IIA metal carbonates is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Classification of Elements and Periodicity (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply