| ⇦ | 
| ⇨ |
The equilibrium weight of MnSO₄ is M/2 when it changes into
Options
(a) KMnO₄
(b) K₂MnO₄
(c) MnO₂
(d) MnO
Correct Answer:
MnO₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The compounds having only primary hydrogen atoms is
- The entropy change in the conversion of a solid into its different states
- The Ca²⁺ and F⁻ are located in CaF₂ crystal,respectively at face centred cubic lattic points
- 20 g of a non-volatile solute is added to 500 g of solvent. Freezing point
- The volume of 0.05 M KMnO₄ solution required to oxidized completely 2.70g
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The compounds having only primary hydrogen atoms is
- The entropy change in the conversion of a solid into its different states
- The Ca²⁺ and F⁻ are located in CaF₂ crystal,respectively at face centred cubic lattic points
- 20 g of a non-volatile solute is added to 500 g of solvent. Freezing point
- The volume of 0.05 M KMnO₄ solution required to oxidized completely 2.70g
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply