The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy

⇦

⇨

The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy of fourth Bohr orbit would be

Options

(a) -41 kJ mol⁻¹
(b) -1312 kJ mol⁻¹
(c) -164 kJ mol⁻¹
(d) -82 kJ mol⁻¹

Correct Answer:

-82 kJ mol⁻¹

Explanation:

The energy of second Bohr orbit of hydrogen atom (E₂) is -328 kJ mol⁻¹therefore,
E₂ = – (1312/2²) kJ mol⁻¹
Eₙ = – (1312/n²) kJ mol⁻¹
If n= 4, E₄ = – (1312/4²) kJ mol⁻¹
= -82 kJ mol⁻¹

Related Questions:

1. The first fractional product of petroleum from top to bottom is
2. Standard reduction potential for Al³⁺/Al , Fe²/Fe, Br/Br are ₋1.66V, ₋0.45V, 1.09V
3. Which of the following is an ore of aluminium
4. In the periodic table going down in fluorine group
5. Considering the state of hybridization of carbon atoms, find out the molecule

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends