The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy

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The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy of fourth Bohr orbit would be

Options

(a) -41 kJ mol⁻¹
(b) -1312 kJ mol⁻¹
(c) -164 kJ mol⁻¹
(d) -82 kJ mol⁻¹

Correct Answer:

-82 kJ mol⁻¹

Explanation:

The energy of second Bohr orbit of hydrogen atom (E₂) is -328 kJ mol⁻¹therefore,
E₂ = – (1312/2²) kJ mol⁻¹
Eₙ = – (1312/n²) kJ mol⁻¹
If n= 4, E₄ = – (1312/4²) kJ mol⁻¹
= -82 kJ mol⁻¹

Related Questions:

1. Which of the following species contains three bond pairs and one lone pair
2. Geometrical isomerism is possible in
3. Carbylamine reaction is given by
4. Total number of isomers possible for the molecular formula C₄H₁₀O is
5. For the reversible reaction,The equilibrium shifts in forward direction

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)

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