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The energy of a hydrogen atom in the ground state is -13.6 eV. The energy of a He⁺ ion in the first excited state will be
Options
(a) – 13.6 eV
(b) – 27.7 eV
(c) – 54.4 eV
(d) – 6.8 eV
Correct Answer:
– 13.6 eV
Explanation:
energy of a H-like atom in its nth state is given by
E = – Z² x 13.6 / n² eV
For, first excited state of He⁺, n= 2, Z= 2
Eₕₑ⁺ = – 4/2² x 13.6 = – 13.6 eV
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- When one of the slits of Young’s experiment is covered with a transport sheet
- A thin wire of length L and mass M is bent to form a semicircle.
- A charged particle with a velocity 2×10³ ms⁻¹ passes undeflected through electric field
- A stationary particle explodes into two particles of masses m₁ and m₂ which move
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Topics: Atoms and Nuclei (136)
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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