⇦ | ⇨ |
The energy of a hydrogen atom in the ground state is -13.6 eV. The energy of a He⁺ ion in the first excited state will be
Options
(a) – 13.6 eV
(b) – 27.7 eV
(c) – 54.4 eV
(d) – 6.8 eV
Correct Answer:
– 13.6 eV
Explanation:
energy of a H-like atom in its nth state is given by
E = – Z² x 13.6 / n² eV
For, first excited state of He⁺, n= 2, Z= 2
Eₕₑ⁺ = – 4/2² x 13.6 = – 13.6 eV
Related Questions: - The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
- An object of mass 3kg is at rest. Now a force F=6t² i⃗+4t j⃗ is applied on the object
- The workdone in turning a magnet of magnetic moment M by an angle of 90⁰ from the magnetic
- In Young’s double slit interference experiment, using two coherent waves
- A particle moving along a straight line OX.At a time (in second ) the distance
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
- An object of mass 3kg is at rest. Now a force F=6t² i⃗+4t j⃗ is applied on the object
- The workdone in turning a magnet of magnetic moment M by an angle of 90⁰ from the magnetic
- In Young’s double slit interference experiment, using two coherent waves
- A particle moving along a straight line OX.At a time (in second ) the distance
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply