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The electronic configuration of a noble gas is
Options
(a) 1s² 2s² 2p⁶3s²
(b) 1s² 2s² 2p⁶
(c) 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
(d) 1s² 2s² 2p⁶3s¹
Correct Answer:
1s² 2s² 2p⁶
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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- Boron is unable to form BF₆³⁻ because of
- In Lassaigne’s test red colour precipitate is obtained which is due to formation
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Topics: P Block Elements in Group 15
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The interatomic distances in H₂ and Cl molecules are 74 and 198 pm respectively
- Boron is unable to form BF₆³⁻ because of
- In Lassaigne’s test red colour precipitate is obtained which is due to formation
- Dihedral angle in staggered form of ethane is
- Heating a mixture of sodium benzoate and soda lime gives
Topics: P Block Elements in Group 15 (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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