![](data:image/svg+xml;charset=utf-8,<svg height="300px" width="600px" xmlns="http://www.w3.org/2000/svg" version="1.1"/>)
The electric potential at the surface of an atomic nucleus (z=50) of radius 9.0×10⁻¹³ cm is
Options
(a) 80 volt
(b) 8×10⁶ volt
(c) 9 volt
(d) 9×10⁵ volt
Correct Answer:
8×10⁶ volt
Explanation:
V = (1 / 4πε₀). q/r
= [9 × 10⁹ × 50 × 1.6 × 10⁻¹⁹] / 9 × 10⁻¹⁵
= 8 × 10⁶ volt
