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The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP up from the engine to the rear wheels.The torque developed by the engine is
Options
(a) 16.58 Nm
(b) 0.022 Nm
(c) 158.31 Nm
(d) 141.6 Nm
Correct Answer:
158.31 Nm
Explanation:
P = τω ⇒ τ = P/ω Given:- P = 80 HP = 80 x 746W = 59860 Nms⁻¹ ω = 3600 rpm = (3600/60) x 2π rad s⁻¹ = 120 π rad s⁻¹ τ = 59680/(120xπ) =158.31 Nm
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Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If sink is at a temperature of -39⁰C and source at 0⁰C, then efficiency will be
- ₉₂U²³⁵ undergoes successive disintegrations with the end product of ₈₂P²⁰³
- A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force
- In vacuum, to travel distance d, light takes time t and in medium to travel distance
- In R-L-C series circuit, the potential differences across each element is 20 V.
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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