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The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP up from the engine to the rear wheels.The torque developed by the engine is
Options
(a) 16.58 Nm
(b) 0.022 Nm
(c) 158.31 Nm
(d) 141.6 Nm
Correct Answer:
158.31 Nm
Explanation:
P = τω ⇒ τ = P/ω Given:- P = 80 HP = 80 x 746W = 59860 Nms⁻¹ ω = 3600 rpm = (3600/60) x 2π rad s⁻¹ = 120 π rad s⁻¹ τ = 59680/(120xπ) =158.31 Nm
Related Questions: - If the momentum of electron is changed by P, then the de-Broglie wavelength
- A beam of electron passes undeflected through mutually perpendicular
- A particle executes simple harmonic oscillations with an amplitude
- A train is moving along a straight path with uniform acceleration
- Light of wavelength 500 nm is incident on a metal with work function 2.28 eV.
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the momentum of electron is changed by P, then the de-Broglie wavelength
- A beam of electron passes undeflected through mutually perpendicular
- A particle executes simple harmonic oscillations with an amplitude
- A train is moving along a straight path with uniform acceleration
- Light of wavelength 500 nm is incident on a metal with work function 2.28 eV.
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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