⇦ | ⇨ |
The dimensions of magnetic field intensity B are
Options
(a) MLT⁻²A⁻¹
(b) MT⁻²A⁻¹
(c) ML²TA⁻²
(d) M²LT⁻²A⁻¹
Correct Answer:
MT⁻²A⁻¹
Explanation:
Dimensions of B = [MT⁻²A⁻¹]
F = Bil sin θ
[MLT⁻²] = [B] [AL]
[B] = [MT⁻²A⁻¹]
Related Questions: - In a mass spectrometer used for measuring the masses of ions, the ions
- Curie is the unit of
- In Young’s double silt experiment if the distance between the two slits
- The sun light reaches us as white and not as its components because
- The innermost orbit of hydrogen atom has a diameter 1.06Å. The diameter of tenth
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a mass spectrometer used for measuring the masses of ions, the ions
- Curie is the unit of
- In Young’s double silt experiment if the distance between the two slits
- The sun light reaches us as white and not as its components because
- The innermost orbit of hydrogen atom has a diameter 1.06Å. The diameter of tenth
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply