| ⇦ |
| ⇨ |
The dimensions of magnetic field intensity B are
Options
(a) MLT⁻²A⁻¹
(b) MT⁻²A⁻¹
(c) ML²TA⁻²
(d) M²LT⁻²A⁻¹
Correct Answer:
MT⁻²A⁻¹
Explanation:
Dimensions of B = [MT⁻²A⁻¹]
F = Bil sin θ
[MLT⁻²] = [B] [AL]
[B] = [MT⁻²A⁻¹]
Related Questions: - “On flowing current in a conducting wire the magnetic field is produced around it”.
- When ₃Li⁷ nuclei are bombarded by protons, and the resultant nuclei are ₄Be⁸,
- Nickel shows ferromagnetic property at room temperature. If the temperature is
- A student performs an experiment to determine the Young’s modulus of a wire
- A satellite in a circular orbit of radius R has a period of 4 hours. Another satellite
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- “On flowing current in a conducting wire the magnetic field is produced around it”.
- When ₃Li⁷ nuclei are bombarded by protons, and the resultant nuclei are ₄Be⁸,
- Nickel shows ferromagnetic property at room temperature. If the temperature is
- A student performs an experiment to determine the Young’s modulus of a wire
- A satellite in a circular orbit of radius R has a period of 4 hours. Another satellite
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply