| ⇦ |
| ⇨ |
The dimensions of magnetic field intensity B are
Options
(a) MLT⁻²A⁻¹
(b) MT⁻²A⁻¹
(c) ML²TA⁻²
(d) M²LT⁻²A⁻¹
Correct Answer:
MT⁻²A⁻¹
Explanation:
Dimensions of B = [MT⁻²A⁻¹]
F = Bil sin θ
[MLT⁻²] = [B] [AL]
[B] = [MT⁻²A⁻¹]
Related Questions: - A spring of spring constant 5 x 10³ Nm⁻¹ is streched intially by 5 cm from
- A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter
- The moment of inertia of a uniform circular disc of radius R and mass M about an axis
- A wave travelling in the +ve x-direction having displacement along y-direction as 1m
- An ideal spring with spring constant K is hung from the ceiling and a block of mass
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A spring of spring constant 5 x 10³ Nm⁻¹ is streched intially by 5 cm from
- A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter
- The moment of inertia of a uniform circular disc of radius R and mass M about an axis
- A wave travelling in the +ve x-direction having displacement along y-direction as 1m
- An ideal spring with spring constant K is hung from the ceiling and a block of mass
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply