| ⇦ |
| ⇨ |
The correct order of the decreasing ionic radii among the following isoelectronic species are :
Options
(a) Ca²⁺ > K⁺ > S²⁻ > Cl⁻
(b) Cl⁻ > S²⁻ >Ca²⁺ > K⁺
(c) S²⁻ > Cl⁻ >K⁺ >Ca²⁺
(d) K⁺ > Ca²⁺ > Cl⁻ > S²⁻
Correct Answer:
S²⁻ > Cl⁻ >K⁺ >Ca²⁺
Explanation:
Among the isoelectronic species, size increases with the increase in negative charge. Thus S has the highest negative charge and hence largest in size followed by Cl, K and Ca
Related Questions: - The structure of benzene is
- Compound that has smell of bitter almonds is
- Transition elements
- Reaction of diborane with ammonia gives initially
- If a 0.00001 M solution of HCl is diluted thousand folds the pH of the resulting
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Classification of Elements and Periodicity
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The structure of benzene is
- Compound that has smell of bitter almonds is
- Transition elements
- Reaction of diborane with ammonia gives initially
- If a 0.00001 M solution of HCl is diluted thousand folds the pH of the resulting
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Classification of Elements and Periodicity (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply