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The correct order of the decreasing ionic radii among the following isoelectronic species are :
Options
(a) Ca²⁺ > K⁺ > S²⁻ > Cl⁻
(b) Cl⁻ > S²⁻ >Ca²⁺ > K⁺
(c) S²⁻ > Cl⁻ >K⁺ >Ca²⁺
(d) K⁺ > Ca²⁺ > Cl⁻ > S²⁻
Correct Answer:
S²⁻ > Cl⁻ >K⁺ >Ca²⁺
Explanation:
Among the isoelectronic species, size increases with the increase in negative charge. Thus S has the highest negative charge and hence largest in size followed by Cl, K and Ca
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Classification of Elements and Periodicity
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Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- According to Bohr’s theory, the angular momentum of electron in 5th orbit is
- When aniline is treated with chloroform in the presence of alcoholic KOH, the product
- The mass of an object changes from 0.002 g to 0.00025 g in a time period
- The complex [CoF₆]⁴⁻ is
- M⁺³ ion loses 3e⁻. Its oxidation number will be
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Classification of Elements and Periodicity (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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