| ⇦ |
| ⇨ |
The correct order in which the O–O bond length increases in the following is
Options
(a) H₂O₂ < O₂ < O₃
(b) O₃ < H₂O₂ < O₂
(c) O₂ < O₃ < H₂O₂
(d) O₂ < H₂O₂ < O₃
Correct Answer:
O₂ < O₃ < H₂O₂
Explanation:
Bond length of O–O in O₂ = 1.21 Å
Bond length of O–O in O₃ = 1.278 Å
Bond length of O–O in H₂O₂ = 1.49 Å
Therefore correct order of O–O bond length is O₂ < O₃ < H₂O₂
Related Questions: - In aqueous solution of H₂O₂ oxidises H₂S
- A mixture of calcium acetate and calcium benzoate on dry distillation gives
- The correct set of four quantum numbers for the valence electron of rubidium atom
- The oxidation state of sulpur in sodium tetrathionate (Na₂S₄O₆) is
- From the colligative properties of solution which one is the best method for
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Chemical Bonding and Molecular Structure
(86)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In aqueous solution of H₂O₂ oxidises H₂S
- A mixture of calcium acetate and calcium benzoate on dry distillation gives
- The correct set of four quantum numbers for the valence electron of rubidium atom
- The oxidation state of sulpur in sodium tetrathionate (Na₂S₄O₆) is
- From the colligative properties of solution which one is the best method for
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply