The correct bond order in the following species is

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The correct bond order in the following species is

Options

(a) O₂²⁺ < O₂⁻ < O₂⁺
(b) O₂⁺ < O₂⁻ < O₂²⁺
(c) O₂⁻ < O₂⁺ < O₂²⁺
(d) O₂²⁺ < O₂⁺ < O₂⁻

Correct Answer:

O₂⁻ < O₂⁺ < O₂²⁺

Explanation:

O₂⁺ ion -Total number of electrons (16-1)=15.

Electronic configuration σ1s² < σ*1s² < σ2s² < σ*2s² < σ2p²(x) < π2p²(y)=π2p²(z)< π*2p¹(y)

Bond order =N(b)-N(a)/2 = 10-5/2 = 5/2 =2 1/2 O⁻₂ (super oxide ion): Total number of electrons (16+1)=17

Electronic configuration σ1s² < σ*1s² < σ2s² < σ*2s² < σ2p²(x) < π2p²(y)=π2p²(z)< π*2p² (y)=π*2p¹(z)

Bond order =N(b)-N(a)/2 = 10-7/2 = 3/2 =1 1/2

O₂⁺² ion :Total number of electrons (16-2)=14.

Electronic configuration σ1s² < σ*1s² < σ2s² < σ*2s² < σ2p²(x) < π2p²(y)=π2p²(z)

Bond order =N(b)-N(a)/2 = 10-4/2 = 6/2 =3

So bond order :O⁻₂ <O₂⁺<O₂²⁺

Related Questions:

1. If the manufacture of bromine from sea water, the mother liquor containing bromides
2. Packing efficiency of hcp structure is
3. In which of the folowing pair both the species have sp³ hybridization?
4. What is the dominant intermolecular force or bond that must be overcome
5. Alum is a water purifier because it

Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)

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