| ⇦ | 
| ⇨ |
The change in oxidation state of sulphur when sulphur dioxide is passed in an acidified K₂Cr₂O₇ solution is from
Options
(a) 4 to 0
(b) 4 to 2
(c) 4 to 6
(d) 6 to 4
Correct Answer:
4 to 6
Explanation:
Acidified K₂Cr₂O₇ solution oxidised SO₂ into Cr₂(SO₄)₃.
3SO₂ + K₂Cr₂O₇ + H₂O → K₂SO₄ + Cr₂(SO₄)₃ + H₂O
Oxidation of S =+4
Oxidation of (SO₄) = +6
Related Questions: - One mole of magnesium nitride on reaction with excess of water gives
- Amount of calcium oxide required, when it reacts with 852 g of P₄O₁₀ is
- At room temperature the eclipsed and staggered forms of ethane can not be isolate
- Hydrolytic reaction of fats, with caustic soda, is known as
- Which of the following alcohol is least soluble in water
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- One mole of magnesium nitride on reaction with excess of water gives
- Amount of calcium oxide required, when it reacts with 852 g of P₄O₁₀ is
- At room temperature the eclipsed and staggered forms of ethane can not be isolate
- Hydrolytic reaction of fats, with caustic soda, is known as
- Which of the following alcohol is least soluble in water
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply