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The change in oxidation state of sulphur when sulphur dioxide is passed in an acidified K₂Cr₂O₇ solution is from
Options
(a) 4 to 0
(b) 4 to 2
(c) 4 to 6
(d) 6 to 4
Correct Answer:
4 to 6
Explanation:
Acidified K₂Cr₂O₇ solution oxidised SO₂ into Cr₂(SO₄)₃.
3SO₂ + K₂Cr₂O₇ + H₂O → K₂SO₄ + Cr₂(SO₄)₃ + H₂O
Oxidation of S =+4
Oxidation of (SO₄) = +6
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Bithional is generally added to the soaps as an additive to function as a
- The cell membranes are mainly composed of
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- Which one is most reactive towards SN1 reaction
- A bromoalkane contains 35% carbon and 6.57% hydrogen by mass. Calculate the empirical
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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