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The case of adsorption of the hydrated alkali metal ions on an ion-exchange resins follows the order:
Options
(a) Li⁺ < K⁺ < Na⁺ < Rb⁺
(b) Rb⁺ < K⁺ < Na⁺ < Li⁺
(c) K⁺ < Na⁺ < Rb⁺ < Li⁺
(d) Na⁺ < Li⁺ < K⁺ < Rb⁺
Correct Answer:
Rb⁺ < K⁺ < Na⁺ < Li⁺
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: S and Some P Block Elements
(157)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Numbers of moles of K₂Cr₂O₇ reduced by one mole os Sn²⁺
- Consider the modes of transformations of a gas from state ‘A’ to state ‘B’
- How many edta molecules can surround calcium
- Which of the following acts as an oxidising as well as reducing agent
- The K(sp) of Ag₂CrO₄, AgCl,AgBr and AgI are respectively. 1.1 ˣ 10⁻¹²,1.8 ˣ 10⁻¹⁰,
Topics: S and Some P Block Elements (157)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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