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The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV, respectively. In the nuclear reaction ₃⁷Li+₁¹H→ ₂⁴He+ ₂⁴He+Q, the value of energy Q released is
Options
(a) 19.6 MeV
(b) (-24 MeV)
(c) 8.4 MeV
(d) 17.3 MeV
Correct Answer:
17.3 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The mass of a ⁷₃ Li nucleus is 0.042 u less than the sum of the masses of all its nucleons
- An engine pumps water continuously through a hose. Water leaves the hose
- If the electric field lines is flowing along axis of a cylinder, then the flux
- Two tangent galvanometers A and B have coils of radii 8 cm and 16 cm respectively
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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