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The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV, respectively. In the nuclear reaction ₃⁷Li+₁¹H→ ₂⁴He+ ₂⁴He+Q, the value of energy Q released is
Options
(a) 19.6 MeV
(b) (-24 MeV)
(c) 8.4 MeV
(d) 17.3 MeV
Correct Answer:
17.3 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 1 µA beam of protons with a cross-sectional area of 0.5 sq.mm is moving with a velocity
- If R is the radius of earth, the height at which the weight of a body 1/4 of its weight
- Two straight wires each 10cm long are parallel to one another and seperated by 2 cm.
- Two nuclei have their mass numbers into the ratio of 1:3
- An electric kettle has two heating elements. One brings it to boil in ten minutes
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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