| ⇦ | 
| ⇨ |
The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV. If two deutrons are fused to form one ₂⁴He then the energy released is
Options
(a) 30.2 MeV
(b) 25.8 MeV
(c) 23.6 MeV
(d) 19.2 MeV
Correct Answer:
23.6 MeV
Explanation:
₁H² + ₁H² → ₂He⁴ + energy
.·. Energy released = B.E or ₂He⁴ – 2(B.E. of ₁H²)
= 28 – 2(2.2) = 28 – 4.4 = 23.6 Mev
Related Questions: - An automobile engine develops 100 kW when rotating at a speed of 1800 rev/min
- For principal quantum number n=3, the possible values of orbital quantum number
- Light of two different frequencies whose photons have energies 1eV
- A thin circular ring of mass M and radius R rotates about an axis through its centre
- The half life of radium is about 1600 year. Of 100 gram of radium existing now
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An automobile engine develops 100 kW when rotating at a speed of 1800 rev/min
- For principal quantum number n=3, the possible values of orbital quantum number
- Light of two different frequencies whose photons have energies 1eV
- A thin circular ring of mass M and radius R rotates about an axis through its centre
- The half life of radium is about 1600 year. Of 100 gram of radium existing now
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply