| ⇦ | 
| ⇨ |
The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV. If two deutrons are fused to form one ₂⁴He then the energy released is
Options
(a) 30.2 MeV
(b) 25.8 MeV
(c) 23.6 MeV
(d) 19.2 MeV
Correct Answer:
23.6 MeV
Explanation:
₁H² + ₁H² → ₂He⁴ + energy
.·. Energy released = B.E or ₂He⁴ – 2(B.E. of ₁H²)
= 28 – 2(2.2) = 28 – 4.4 = 23.6 Mev
Related Questions: - A ray of light is incident at an angle of incidence i, on one face of a prism
- By sucking through a straw, a student can reduce the pressure of his lungs
- Masses of three wires of copper are in the ratio of 1:3:5 and their lengths
- A rod lies along the X-axis with one end at the origin and the other at x→∞. It carries
- The escape velocity from the earth’s surface is 11 kms⁻¹.A certain planet
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A ray of light is incident at an angle of incidence i, on one face of a prism
- By sucking through a straw, a student can reduce the pressure of his lungs
- Masses of three wires of copper are in the ratio of 1:3:5 and their lengths
- A rod lies along the X-axis with one end at the origin and the other at x→∞. It carries
- The escape velocity from the earth’s surface is 11 kms⁻¹.A certain planet
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply