The acceleration of an electron in an electric field of magnitude 50 V/cm,

The acceleration of an electron in an electric field of magnitude 50 V/cm, if e/m value of the electron is 1.76×10¹¹ C/kg will be

(a) 8.8×10¹⁴ m/sec²
(b) 3×10¹³ m/sec²
(c) 5.4×10¹² m/sec²
(d) Zero

8.8×10¹⁴ m/sec²

Acceleration = a = eE / m

⇒ a = 1.76 × 10¹¹ × 50 × 10 ¹²

⇒ a = 8.8 × 10 ¹⁴ m/ sec²

UP2001

admin:

Sakshi says:

May 22, 2020 at 10:37 pm

E=50v/cm
=5000v/m
e/m=1.76×10power-11
F=ma
F=qĒ
ma=qĒ
a= e/m×Ē
=1.76×10 power11 × 5000
=8.8×10 power 14 m/sec sq.