| ⇦ | 
| ⇨ |
Strong reducing behaviour of H₃PO₂ is due to
Options
(a) high electron gain enthalpy of phosphorus
(b) high oxidation state of phosphorus
(c) presence of two –OH groups and one P–H bond
(d) presence of one –OH group and two P–H bonds
Correct Answer:
presence of one –OH group and two P–H bonds
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which one of the elements has the highest ionisation energy?
- Highest electron affinity is shown by
- Bohr’s theory was modified to give the concept of elliptical orbits by
- Aluminium oxide is not reduced by chemical reaction since
- In the extraction of copper from its sulphide ore, the metal is finally obtained
Topics: P Block Elements in Group 15
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the elements has the highest ionisation energy?
- Highest electron affinity is shown by
- Bohr’s theory was modified to give the concept of elliptical orbits by
- Aluminium oxide is not reduced by chemical reaction since
- In the extraction of copper from its sulphide ore, the metal is finally obtained
Topics: P Block Elements in Group 15 (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply