| ⇦ | 
| ⇨ |
Standard entropies of X₂, Y₂ and XY₃ are 60, 40 and 50 J K⁻¹ mol⁻¹ respectively. For the reaction 1/2X₂ + 3/2Y₂ ⇌ XY₃,ΔH = -30 kJ, to be at equilibrium ,the temperature should be
Options
(a) 750 K
(b) 1000 K
(c) 1250 K
(d) 500 K
Correct Answer:
750 K
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A device that converts energy of combustion of fuels like hydrogen and methane,
- 40 mL of 0.1 M ammonia solution is mixed with 20 mL of 0.1 M HCl.
- α-D-glucose and β-D-glucose are
- Which of the following statements is incorrect
- Order of reaction is decided by
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A device that converts energy of combustion of fuels like hydrogen and methane,
- 40 mL of 0.1 M ammonia solution is mixed with 20 mL of 0.1 M HCl.
- α-D-glucose and β-D-glucose are
- Which of the following statements is incorrect
- Order of reaction is decided by
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply