| ⇦ |
| ⇨ |
Standard entropies of X₂, Y₂ and XY₃ are 60, 40 and 50 J K⁻¹ mol⁻¹ respectively. For the reaction 1/2X₂ + 3/2Y₂ ⇌ XY₃,ΔH = -30 kJ, to be at equilibrium ,the temperature should be
Options
(a) 750 K
(b) 1000 K
(c) 1250 K
(d) 500 K
Correct Answer:
750 K
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An organic compound gives Molisch’s test as well as Benedict’s test.
- Activated charcoal is used to remove colouring matter from pure substances.
- Assuming fully decomposed, the volume of CO₂ released at STP on heating 9.85g
- The density of methane (CH₄) at 2.0 atmospheric pressure and 27⁰C is
- If one strand of DNA has the sequence ATGCTTGA,the sequence in the complementary
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An organic compound gives Molisch’s test as well as Benedict’s test.
- Activated charcoal is used to remove colouring matter from pure substances.
- Assuming fully decomposed, the volume of CO₂ released at STP on heating 9.85g
- The density of methane (CH₄) at 2.0 atmospheric pressure and 27⁰C is
- If one strand of DNA has the sequence ATGCTTGA,the sequence in the complementary
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply