| ⇦ |
| ⇨ |
Reaction of solid KMnO₄ with conc.H₂SO₄ produces manganese heptoxide (Mn₂O₇) in
Options
(a) solution state
(b) solid state
(c) fine powder
(d) none of these
Correct Answer:
solution state
Explanation:
KMnO₄ on treatment with concentrated H₂SO₄ forms manganese heptoxide via permanganyl sulphate which decomposes explosively on heating. 2KMnO₄ + 3H₂SO₄ → 2KHSO₄ + (MnO₃)₂SO₄ + 2H₂O. (MnO₃)₂SO₄ + H₂O → Mn₂O₇(Red-brown liquid) + H₂SO₄. Mn₂O₇ → 2MnO₂ + 3/2 O₂. Therefore Mn₂O₇ so formed is a red-brown liquid.
Related Questions: - The heat of neutralization of a strong base and a strong acid is 57 kJ.
- If 10 cm³ solution of H₂O₂ ,on decomposition gives 150 cm³ of O₂
- First ionization potential of Mg is
- Which is not the property transition elements
- Which of the following compounds gives trichloromethane on distilling with
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The heat of neutralization of a strong base and a strong acid is 57 kJ.
- If 10 cm³ solution of H₂O₂ ,on decomposition gives 150 cm³ of O₂
- First ionization potential of Mg is
- Which is not the property transition elements
- Which of the following compounds gives trichloromethane on distilling with
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply