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Radius of orbit of satellite of earth is R. Its kinetic energy is proportional to
Options
(a) 1/R
(b) 1/√R
(c) R
(d) 1/R³/²
Correct Answer:
1/R
Explanation:
Kinetic energy of the satellite=1/2mv₀²
v₀=√GM/R
Now, Putting the value of v₀, We get,
Kinetic energy=1/2m(√GM/R)²
=1/2 GMm/R
Therefore, Kinetic energy is proportional to 1/R.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
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