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Point masses m₁ and m₂ are placed at the opposite ends of a rigid rod of length L, and negligible mass. The rod is to be set rotating about an axis perpendicular to it. The position of point P on this rod through which the axis should pass so that the work required to set the rod rotating with angular velocity ω₀ is minimum, is given by
Options
(a) x= m₂/m₁ L
(b) x= m₂L/m₁+m₂
(c) x= m₁L/m₁+m₂
(d) x= m₁/m₂ L
Correct Answer:
x= m₂L/m₁+m₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two slits in Young’s experiment have widths in the ratio 1:25. The ratio of intensity
- In refraction, light waves are bent on passing from one medium to the second medium
- For non-conductors, the energy gap is
- An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by
- The angle of incidence at which reflected light is totally polarised for refraction
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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