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Point masses m₁ and m₂ are placed at the opposite ends of a rigid rod of length L, and negligible mass. The rod is to be set rotating about an axis perpendicular to it. The position of point P on this rod through which the axis should pass so that the work required to set the rod rotating with angular velocity ω₀ is minimum, is given by
Options
(a) x= m₂/m₁ L
(b) x= m₂L/m₁+m₂
(c) x= m₁L/m₁+m₂
(d) x= m₁/m₂ L
Correct Answer:
x= m₂L/m₁+m₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The time period of bar magnet is doubled when magnetic field is reduced
- If the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy
- A block of mass 4 kg is kept on a rough horizontal surface.The coefficient of static
- A thermocouple is made from two metals, antimony and bismuth. If one junction
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Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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