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Point masses m₁ and m₂ are placed at the opposite ends of a rigid rod of length L, and negligible mass. The rod is to be set rotating about an axis perpendicular to it. The position of point P on this rod through which the axis should pass so that the work required to set the rod rotating with angular velocity ω₀ is minimum, is given by
Options
(a) x= m₂/m₁ L
(b) x= m₂L/m₁+m₂
(c) x= m₁L/m₁+m₂
(d) x= m₁/m₂ L
Correct Answer:
x= m₂L/m₁+m₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Surface tension of water will be minimum at
- The molecular weight of a gas is 44. The volume occupied by 2.2 g of this gas
- A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field
- A moving neutron collides with a stationary α-particle.The fraction of the kinetic energy
- A gas is suddenly expanded such that its final volume becomes 3 times
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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