Navigate

Periodic time of a satellite revolving above Earth’s surface at a height equal to R,

Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)

Options

(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g

Correct Answer:

4√2√R/g

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

MP2002
admin:

Related Questions

  1. The nuclear radius of a certain nucleus is 7.2 fm and it has a charge of 1.28×10⁻¹⁷ C.
  2. A force F=ai+3j+6k is acting at a point r=2i-6j-12k. The value of α for
  3. A heavy nucleus at rest breaks into two fragments which fly off with velocities
  4. A horizontal straight conductor kept in north-south direction falls under gravity. Then
  5. When a beam of light is used to determine the position of an object,