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Oxidation state of sulphur in S₈, H₂S and S₂F₂ is
Options
(a) 0, -2, -1
(b) 0, 2, -1
(c) 1, -2, 1
(d) 0, -2, 1
Correct Answer:
0, -2, 1
Explanation:
Oxidation state of Sulphur in S₈ = 0,
Sulphur in H₂S = 2+x = 0, x = -2,
Sulphur in S₂F₂ = 2x + 2(-1) = 0,
2x – 2 = 0, x = 1.
Related Questions: - pH value of a solution, whose hydronium ion concentration is 6.2 x 10⁻⁹ mol/L is
- Least voltage hydrogen halide is
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Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- pH value of a solution, whose hydronium ion concentration is 6.2 x 10⁻⁹ mol/L is
- Least voltage hydrogen halide is
- CN⁻ is a strong fields ligand.This is due to the fact that
- In the dichlorination reaction of propane, mixture of products are obtained.
- If concentration of reactants is increased by ‘x’,then the K becomes
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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