Oxidation state of sulphur in S₈, H₂S and S₂F₂ is

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Oxidation state of sulphur in S₈, H₂S and S₂F₂ is

Options

(a) 0, -2, -1
(b) 0, 2, -1
(c) 1, -2, 1
(d) 0, -2, 1

Correct Answer:

0, -2, 1

Explanation:

Oxidation state of Sulphur in S₈ = 0,
Sulphur in H₂S = 2+x = 0, x = -2,
Sulphur in S₂F₂ = 2x + 2(-1) = 0,
2x – 2 = 0, x = 1.

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Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)

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