| ⇦ | 
| ⇨ |
Oxidation state of sulphur in S₈, H₂S and S₂F₂ is
Options
(a) 0, -2, -1
(b) 0, 2, -1
(c) 1, -2, 1
(d) 0, -2, 1
Correct Answer:
0, -2, 1
Explanation:
Oxidation state of Sulphur in S₈ = 0,
Sulphur in H₂S = 2+x = 0, x = -2,
Sulphur in S₂F₂ = 2x + 2(-1) = 0,
2x – 2 = 0, x = 1.
Related Questions: - Radius ratio of an ionic compound is 0.93. The structure of the above
- If the hydrogen ion concentration of an acid decreases 10 times, its pH value
- Schottky defect defines imperfection in the lattice structure of a
- Salicylic acids is prepared from phenol by
- Which of the following reagents can be used to convert primary amides into pri
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Radius ratio of an ionic compound is 0.93. The structure of the above
- If the hydrogen ion concentration of an acid decreases 10 times, its pH value
- Schottky defect defines imperfection in the lattice structure of a
- Salicylic acids is prepared from phenol by
- Which of the following reagents can be used to convert primary amides into pri
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply