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Oxidation state of sulphur in S₈, H₂S and S₂F₂ is
Options
(a) 0, -2, -1
(b) 0, 2, -1
(c) 1, -2, 1
(d) 0, -2, 1
Correct Answer:
0, -2, 1
Explanation:
Oxidation state of Sulphur in S₈ = 0,
Sulphur in H₂S = 2+x = 0, x = -2,
Sulphur in S₂F₂ = 2x + 2(-1) = 0,
2x – 2 = 0, x = 1.
Related Questions: - Which of the following is the most electropositive element
- Oxygen is more electrnegative than sulphur, yet H₂S is acidic in nature
- The ratio of charge and mass would be greatest for
- Acetanilide can be prepared,from aniline with
- A helium, molecule is two times heavier than a hydrogen molecule at 298 K
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is the most electropositive element
- Oxygen is more electrnegative than sulphur, yet H₂S is acidic in nature
- The ratio of charge and mass would be greatest for
- Acetanilide can be prepared,from aniline with
- A helium, molecule is two times heavier than a hydrogen molecule at 298 K
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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