| ⇦ | 
| ⇨ |
One mole of a gas absorbs 300 J of heat at constant volume and its temperature is raised from 30 to 35⁰C. The value of ΔE is
Options
(a) 300 J
(b) 0.1 J
(c) 150 J
(d) 200 J
Correct Answer:
300 J
Explanation:
ΔE = Qv (heat change under constant volume).
Related Questions: - The number of electrons involved in the reduction of one nitrate ion
- Which of the following will be most stable diazonium salt RN₂⁺ X⁻
- At 25⁰ C , the highest osmotic pressure is exhibited by 0.1 M solution of
- Which of the following solutions boils at the highest temperature
- If 18g of water is electrolysed then volume of oxygen obtained at STP is
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The number of electrons involved in the reduction of one nitrate ion
- Which of the following will be most stable diazonium salt RN₂⁺ X⁻
- At 25⁰ C , the highest osmotic pressure is exhibited by 0.1 M solution of
- Which of the following solutions boils at the highest temperature
- If 18g of water is electrolysed then volume of oxygen obtained at STP is
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply