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On doubling P and V with constant temperature the equilibrium constant will
Options
(a) remain constant
(b) become double
(c) become one-fourth
(d) none of these
Correct Answer:
remain constant
Explanation:
On doubling P and volume with constant T, the equilibrium constant (K) will remain constant. Pressure will never affect the value of K. It may result in the shifting of equilibrium but not the equilibrium constant value. Temperature always changes K because on adding heat to a system in state of equilibrium will always alter the forward reaction rate differently than the reverse reaction rate. Also by doubling the volume, the concentrations of both reactants and product evenly become half. Therefore, overall there is no change in equilibrium constant value (K).
Related Questions: - If α is dissociation constant, then the total number of moles for the reaction
- Of the following which one is classified as polymer
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Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If α is dissociation constant, then the total number of moles for the reaction
- Of the following which one is classified as polymer
- From the colligative properties of solution which one is the best method for
- The number of spherical nodes in 3p orbitals are
- What is the magnetic moment for Mn²⁺ ion in low spin state
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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